2(4x-7)^2+5=37-5

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Solution for 2(4x-7)^2+5=37-5 equation:



2(4x-7)^2+5=37-5
We move all terms to the left:
2(4x-7)^2+5-(37-5)=0
We add all the numbers together, and all the variables
2(4x-7)^2+5-32=0
We add all the numbers together, and all the variables
2(4x-7)^2-27=0
We move all terms containing x to the left, all other terms to the right
2(4x-7)^2=27

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